Base | Representation |
---|---|
bin | 10000000110111010110… |
… | …01000000010010101001 |
3 | 1221220121021200221000021 |
4 | 20003131121000102221 |
5 | 33032001323232132 |
6 | 1102132145440441 |
7 | 54662335340215 |
oct | 10033531002251 |
9 | 1856537627007 |
10 | 553470133417 |
11 | 1a37a8509103 |
12 | 8b324040121 |
13 | 40265acaa86 |
14 | 1cb06779945 |
15 | e5e4e85997 |
hex | 80dd6404a9 |
553470133417 has 2 divisors, whose sum is σ = 553470133418. Its totient is φ = 553470133416.
The previous prime is 553470133379. The next prime is 553470133429. The reversal of 553470133417 is 714331074355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 392553624681 + 160916508736 = 626541^2 + 401144^2 .
It is a cyclic number.
It is not a de Polignac number, because 553470133417 - 215 = 553470100649 is a prime.
It is not a weakly prime, because it can be changed into another prime (553470130417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276735066708 + 276735066709.
It is an arithmetic number, because the mean of its divisors is an integer number (276735066709).
Almost surely, 2553470133417 is an apocalyptic number.
It is an amenable number.
553470133417 is a deficient number, since it is larger than the sum of its proper divisors (1).
553470133417 is an equidigital number, since it uses as much as digits as its factorization.
553470133417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 529200, while the sum is 43.
The spelling of 553470133417 in words is "five hundred fifty-three billion, four hundred seventy million, one hundred thirty-three thousand, four hundred seventeen".
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