Base | Representation |
---|---|
bin | 10000000110111010110… |
… | …01000000010011001011 |
3 | 1221220121021200221001112 |
4 | 20003131121000103023 |
5 | 33032001323232301 |
6 | 1102132145440535 |
7 | 54662335340264 |
oct | 10033531002313 |
9 | 1856537627045 |
10 | 553470133451 |
11 | 1a37a8509134 |
12 | 8b32404014b |
13 | 40265acaab1 |
14 | 1cb0677996b |
15 | e5e4e859bb |
hex | 80dd6404cb |
553470133451 has 2 divisors, whose sum is σ = 553470133452. Its totient is φ = 553470133450.
The previous prime is 553470133429. The next prime is 553470133459. The reversal of 553470133451 is 154331074355.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-553470133451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 553470133399 and 553470133408.
It is not a weakly prime, because it can be changed into another prime (553470133459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276735066725 + 276735066726.
It is an arithmetic number, because the mean of its divisors is an integer number (276735066726).
Almost surely, 2553470133451 is an apocalyptic number.
553470133451 is a deficient number, since it is larger than the sum of its proper divisors (1).
553470133451 is an equidigital number, since it uses as much as digits as its factorization.
553470133451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378000, while the sum is 41.
The spelling of 553470133451 in words is "five hundred fifty-three billion, four hundred seventy million, one hundred thirty-three thousand, four hundred fifty-one".
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