Base | Representation |
---|---|
bin | 10000000110111010111… |
… | …01101111000110010001 |
3 | 1221220121101000221101011 |
4 | 20003131131233012101 |
5 | 33032002132424323 |
6 | 1102132232210521 |
7 | 54662352024226 |
oct | 10033535570621 |
9 | 1856541027334 |
10 | 553471373713 |
11 | 1a37a9185a45 |
12 | 8b324539a41 |
13 | 4026614348b |
14 | 1cb069bd94d |
15 | e5e512d20d |
hex | 80dd76f191 |
553471373713 has 2 divisors, whose sum is σ = 553471373714. Its totient is φ = 553471373712.
The previous prime is 553471373701. The next prime is 553471373743. The reversal of 553471373713 is 317373174355.
553471373713 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 461778688849 + 91692684864 = 679543^2 + 302808^2 .
It is a cyclic number.
It is not a de Polignac number, because 553471373713 - 29 = 553471373201 is a prime.
It is not a weakly prime, because it can be changed into another prime (553471373743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276735686856 + 276735686857.
It is an arithmetic number, because the mean of its divisors is an integer number (276735686857).
Almost surely, 2553471373713 is an apocalyptic number.
It is an amenable number.
553471373713 is a deficient number, since it is larger than the sum of its proper divisors (1).
553471373713 is an equidigital number, since it uses as much as digits as its factorization.
553471373713 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2778300, while the sum is 49.
The spelling of 553471373713 in words is "five hundred fifty-three billion, four hundred seventy-one million, three hundred seventy-three thousand, seven hundred thirteen".
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