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553501414003 is a prime number
BaseRepresentation
bin10000000110111110100…
…00010101001001110011
31221220200110120010220111
420003133100111021303
533032032330222003
61102135224122151
754663165251236
oct10033720251163
91856613503814
10553501414003
111a381413372a
128b332606357
134026c4308b5
141cb0a99d41d
15e5e7ab3e6d
hex80df415273

553501414003 has 2 divisors, whose sum is σ = 553501414004. Its totient is φ = 553501414002.

The previous prime is 553501413947. The next prime is 553501414009. The reversal of 553501414003 is 300414105355.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-553501414003 is a prime.

It is not a weakly prime, because it can be changed into another prime (553501414009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276750707001 + 276750707002.

It is an arithmetic number, because the mean of its divisors is an integer number (276750707002).

Almost surely, 2553501414003 is an apocalyptic number.

553501414003 is a deficient number, since it is larger than the sum of its proper divisors (1).

553501414003 is an equidigital number, since it uses as much as digits as its factorization.

553501414003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 553501414003 its reverse (300414105355), we get a palindrome (853915519358).

The spelling of 553501414003 in words is "five hundred fifty-three billion, five hundred one million, four hundred fourteen thousand, three".