Base | Representation |
---|---|
bin | 11001001011100111010001… |
… | …10111010101111001101111 |
3 | 21021001202120211200110020012 |
4 | 30211303220313111321233 |
5 | 24224224213022424100 |
6 | 313434430204043435 |
7 | 14443453556023565 |
oct | 1445635067257157 |
9 | 237052524613205 |
10 | 55374625201775 |
11 | 1670a279349520 |
12 | 6263b81b3357b |
13 | 24b8a60062769 |
14 | d962090c5a35 |
15 | 66064b221135 |
hex | 325ce8dd5e6f |
55374625201775 has 12 divisors (see below), whose sum is σ = 74906765727864. Its totient is φ = 40272454692000.
The previous prime is 55374625201769. The next prime is 55374625201811. The reversal of 55374625201775 is 57710252647355.
It is not a de Polignac number, because 55374625201775 - 212 = 55374625197679 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 100681136456 + ... + 100681137005.
It is an arithmetic number, because the mean of its divisors is an integer number (6242230477322).
Almost surely, 255374625201775 is an apocalyptic number.
55374625201775 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55374625201775 is a deficient number, since it is larger than the sum of its proper divisors (19532140526089).
55374625201775 is a wasteful number, since it uses less digits than its factorization.
55374625201775 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201362273482 (or 201362273477 counting only the distinct ones).
The product of its (nonzero) digits is 61740000, while the sum is 59.
The spelling of 55374625201775 in words is "fifty-five trillion, three hundred seventy-four billion, six hundred twenty-five million, two hundred one thousand, seven hundred seventy-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •