Base | Representation |
---|---|
bin | 11001001011110011010110… |
… | …01011100001000111111001 |
3 | 21021002101022112101022110012 |
4 | 30211321223023201013321 |
5 | 24224331001230332433 |
6 | 313441421252431305 |
7 | 14444103306100235 |
oct | 1445715313410771 |
9 | 237071275338405 |
10 | 55381106495993 |
11 | 16711aa491a823 |
12 | 6265290618535 |
13 | 24b9553a642b5 |
14 | d96661bbb5c5 |
15 | 6608ca229848 |
hex | 325e6b2e11f9 |
55381106495993 has 2 divisors, whose sum is σ = 55381106495994. Its totient is φ = 55381106495992.
The previous prime is 55381106495969. The next prime is 55381106496031. The reversal of 55381106495993 is 39959460118355.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55093625010064 + 287481485929 = 7422508^2 + 536173^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55381106495993 is a prime.
It is not a weakly prime, because it can be changed into another prime (55381106495293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27690553247996 + 27690553247997.
It is an arithmetic number, because the mean of its divisors is an integer number (27690553247997).
Almost surely, 255381106495993 is an apocalyptic number.
It is an amenable number.
55381106495993 is a deficient number, since it is larger than the sum of its proper divisors (1).
55381106495993 is an equidigital number, since it uses as much as digits as its factorization.
55381106495993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 157464000, while the sum is 68.
The spelling of 55381106495993 in words is "fifty-five trillion, three hundred eighty-one billion, one hundred six million, four hundred ninety-five thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •