Base | Representation |
---|---|
bin | 110011100101100101… |
… | …101100111010110011 |
3 | 12021222022211101122022 |
4 | 303211211230322303 |
5 | 1401420204121311 |
6 | 41240235302055 |
7 | 4000436516615 |
oct | 634545547263 |
9 | 167868741568 |
10 | 55391473331 |
11 | 21545051837 |
12 | a89a5aa92b |
13 | 52b9a45b2c |
14 | 29767b6db5 |
15 | 1692d785db |
hex | ce596ceb3 |
55391473331 has 2 divisors, whose sum is σ = 55391473332. Its totient is φ = 55391473330.
The previous prime is 55391473307. The next prime is 55391473369. The reversal of 55391473331 is 13337419355.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55391473331 - 214 = 55391456947 is a prime.
It is a super-2 number, since 2×553914733312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55394473331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27695736665 + 27695736666.
It is an arithmetic number, because the mean of its divisors is an integer number (27695736666).
Almost surely, 255391473331 is an apocalyptic number.
55391473331 is a deficient number, since it is larger than the sum of its proper divisors (1).
55391473331 is an equidigital number, since it uses as much as digits as its factorization.
55391473331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 510300, while the sum is 44.
The spelling of 55391473331 in words is "fifty-five billion, three hundred ninety-one million, four hundred seventy-three thousand, three hundred thirty-one".
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