Base | Representation |
---|---|
bin | 100001000001011… |
… | …001010110101001 |
3 | 1102121110211111112 |
4 | 201001121112221 |
5 | 2113311422441 |
6 | 130550240105 |
7 | 16505020343 |
oct | 4101312651 |
9 | 1377424445 |
10 | 554014121 |
11 | 2647aa011 |
12 | 135656035 |
13 | 8aa1760b |
14 | 53816293 |
15 | 339874eb |
hex | 210595a9 |
554014121 has 2 divisors, whose sum is σ = 554014122. Its totient is φ = 554014120.
The previous prime is 554014093. The next prime is 554014147. The reversal of 554014121 is 121410455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 363436096 + 190578025 = 19064^2 + 13805^2 .
It is a cyclic number.
It is not a de Polignac number, because 554014121 - 226 = 486905257 is a prime.
It is a super-3 number, since 3×5540141213 (a number of 27 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (554014151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277007060 + 277007061.
It is an arithmetic number, because the mean of its divisors is an integer number (277007061).
Almost surely, 2554014121 is an apocalyptic number.
It is an amenable number.
554014121 is a deficient number, since it is larger than the sum of its proper divisors (1).
554014121 is an equidigital number, since it uses as much as digits as its factorization.
554014121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 800, while the sum is 23.
The square root of 554014121 is about 23537.5045618689. The cubic root of 554014121 is about 821.3096862826.
Adding to 554014121 its reverse (121410455), we get a palindrome (675424576).
The spelling of 554014121 in words is "five hundred fifty-four million, fourteen thousand, one hundred twenty-one".
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