Base | Representation |
---|---|
bin | 110011100110110110… |
… | …110010000110111001 |
3 | 12022000210211020220111 |
4 | 303212312302012321 |
5 | 1401441124300444 |
6 | 41242315024321 |
7 | 4001115263404 |
oct | 634666620671 |
9 | 168023736814 |
10 | 55412728249 |
11 | 2155604998a |
12 | a8a573b0a1 |
13 | 52c12784c8 |
14 | 297954ad3b |
15 | 1694b76234 |
hex | ce6db21b9 |
55412728249 has 2 divisors, whose sum is σ = 55412728250. Its totient is φ = 55412728248.
The previous prime is 55412728243. The next prime is 55412728271. The reversal of 55412728249 is 94282721455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55204791849 + 207936400 = 234957^2 + 14420^2 .
It is a cyclic number.
It is not a de Polignac number, because 55412728249 - 29 = 55412727737 is a prime.
It is not a weakly prime, because it can be changed into another prime (55412728243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27706364124 + 27706364125.
It is an arithmetic number, because the mean of its divisors is an integer number (27706364125).
Almost surely, 255412728249 is an apocalyptic number.
It is an amenable number.
55412728249 is a deficient number, since it is larger than the sum of its proper divisors (1).
55412728249 is an equidigital number, since it uses as much as digits as its factorization.
55412728249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1612800, while the sum is 49.
The spelling of 55412728249 in words is "fifty-five billion, four hundred twelve million, seven hundred twenty-eight thousand, two hundred forty-nine".
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