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55413990799200 = 25312521117241
BaseRepresentation
bin11001001100110000100110…
…01111001011011101100000
321021012112012022000000000000
430212120103033023131200
524230400323121033300
6313504500321300000
714446346231052315
oct1446302317133540
9237175168000000
1055413990799200
1116724a3a191510
12626b729494600
1324bc694862587
14d980a1312d0c
156616a2191c00
hex3266133cb760

55413990799200 has 2808 divisors, whose sum is σ = 240889127437224. Its totient is φ = 12335099904000.

The previous prime is 55413990799163. The next prime is 55413990799273. The reversal of 55413990799200 is 299709931455.

55413990799200 is a `hidden beast` number, since 5 + 5 + 413 + 9 + 9 + 0 + 7 + 9 + 9 + 200 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 467 ways as a sum of consecutive naturals, for example, 1351560751180 + ... + 1351560751220.

Almost surely, 255413990799200 is an apocalyptic number.

55413990799200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 55413990799200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (120444563718612).

55413990799200 is an abundant number, since it is smaller than the sum of its proper divisors (185475136638024).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

55413990799200 is an equidigital number, since it uses as much as digits as its factorization.

55413990799200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142 (or 79 counting only the distinct ones).

The product of its (nonzero) digits is 27556200, while the sum is 63.

The spelling of 55413990799200 in words is "fifty-five trillion, four hundred thirteen billion, nine hundred ninety million, seven hundred ninety-nine thousand, two hundred".