Base | Representation |
---|---|
bin | 11001001101000100000011… |
… | …01101101001010001100011 |
3 | 21021020112011010010102212021 |
4 | 30212202001231221101203 |
5 | 24231033220124321422 |
6 | 313513344504042311 |
7 | 14450166101445616 |
oct | 1446420155512143 |
9 | 237215133112767 |
10 | 55424434213987 |
11 | 16729409224623 |
12 | 6271762a63397 |
13 | 24c066a382257 |
14 | d987b22dc17d |
15 | 661ab3e3bdc7 |
hex | 326881b69463 |
55424434213987 has 2 divisors, whose sum is σ = 55424434213988. Its totient is φ = 55424434213986.
The previous prime is 55424434213913. The next prime is 55424434213991. The reversal of 55424434213987 is 78931243442455.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55424434213987 - 215 = 55424434181219 is a prime.
It is a super-3 number, since 3×554244342139873 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (55424434213487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27712217106993 + 27712217106994.
It is an arithmetic number, because the mean of its divisors is an integer number (27712217106994).
Almost surely, 255424434213987 is an apocalyptic number.
55424434213987 is a deficient number, since it is larger than the sum of its proper divisors (1).
55424434213987 is an equidigital number, since it uses as much as digits as its factorization.
55424434213987 is an evil number, because the sum of its binary digits is even.
The product of its digits is 116121600, while the sum is 61.
The spelling of 55424434213987 in words is "fifty-five trillion, four hundred twenty-four billion, four hundred thirty-four million, two hundred thirteen thousand, nine hundred eighty-seven".
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