Base | Representation |
---|---|
bin | 11001001101000100000011… |
… | …01101101001010001110011 |
3 | 21021020112011010010102212212 |
4 | 30212202001231221101303 |
5 | 24231033220124322003 |
6 | 313513344504042335 |
7 | 14450166101445641 |
oct | 1446420155512163 |
9 | 237215133112785 |
10 | 55424434214003 |
11 | 16729409224638 |
12 | 6271762a633ab |
13 | 24c066a38226a |
14 | d987b22dc191 |
15 | 661ab3e3bdd8 |
hex | 326881b69473 |
55424434214003 has 8 divisors (see below), whose sum is σ = 56681536783872. Its totient is φ = 54170575781256.
The previous prime is 55424434213991. The next prime is 55424434214041. The reversal of 55424434214003 is 30041243442455.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55424434214003 - 24 = 55424434213987 is a prime.
It is a super-3 number, since 3×554244342140033 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55424434214053) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 810999725 + ... + 811068062.
It is an arithmetic number, because the mean of its divisors is an integer number (7085192097984).
Almost surely, 255424434214003 is an apocalyptic number.
55424434214003 is a deficient number, since it is larger than the sum of its proper divisors (1257102569869).
55424434214003 is a wasteful number, since it uses less digits than its factorization.
55424434214003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1622068561.
The product of its (nonzero) digits is 921600, while the sum is 41.
Adding to 55424434214003 its reverse (30041243442455), we get a palindrome (85465677656458).
The spelling of 55424434214003 in words is "fifty-five trillion, four hundred twenty-four billion, four hundred thirty-four million, two hundred fourteen thousand, three".
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