Base | Representation |
---|---|
bin | 10000001000100000101… |
… | …11111110000011100001 |
3 | 1221222210220020001112212 |
4 | 20010100113332003201 |
5 | 33040224312001004 |
6 | 1102353103131505 |
7 | 55022463002552 |
oct | 10042027760341 |
9 | 1858726201485 |
10 | 554325500129 |
11 | 1a40a7325845 |
12 | 8b5225a3b95 |
13 | 40371097a1b |
14 | 1cb881d8329 |
15 | e6450e796e |
hex | 81105fe0e1 |
554325500129 has 2 divisors, whose sum is σ = 554325500130. Its totient is φ = 554325500128.
The previous prime is 554325500083. The next prime is 554325500147. The reversal of 554325500129 is 921005523455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 527763019729 + 26562480400 = 726473^2 + 162980^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-554325500129 is a prime.
It is not a weakly prime, because it can be changed into another prime (554325508129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277162750064 + 277162750065.
It is an arithmetic number, because the mean of its divisors is an integer number (277162750065).
Almost surely, 2554325500129 is an apocalyptic number.
It is an amenable number.
554325500129 is a deficient number, since it is larger than the sum of its proper divisors (1).
554325500129 is an equidigital number, since it uses as much as digits as its factorization.
554325500129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270000, while the sum is 41.
The spelling of 554325500129 in words is "five hundred fifty-four billion, three hundred twenty-five million, five hundred thousand, one hundred twenty-nine".
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