Base | Representation |
---|---|
bin | 11001001101100110111001… |
… | …01111111001011010011001 |
3 | 21021022022102211222222000112 |
4 | 30212303130233321122121 |
5 | 24231340023144301332 |
6 | 313530121052014105 |
7 | 14451430505062304 |
oct | 1446633457713231 |
9 | 237268384888015 |
10 | 55443141400217 |
11 | 16736338a1450a |
12 | 6275303a61335 |
13 | 24c235bc69b0c |
14 | d99668a13b3b |
15 | 66230b436db2 |
hex | 326cdcbf9699 |
55443141400217 has 2 divisors, whose sum is σ = 55443141400218. Its totient is φ = 55443141400216.
The previous prime is 55443141400201. The next prime is 55443141400237. The reversal of 55443141400217 is 71200414134455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 45381995131456 + 10061146268761 = 6736616^2 + 3171931^2 .
It is a cyclic number.
It is not a de Polignac number, because 55443141400217 - 24 = 55443141400201 is a prime.
It is not a weakly prime, because it can be changed into another prime (55443141400237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27721570700108 + 27721570700109.
It is an arithmetic number, because the mean of its divisors is an integer number (27721570700109).
Almost surely, 255443141400217 is an apocalyptic number.
It is an amenable number.
55443141400217 is a deficient number, since it is larger than the sum of its proper divisors (1).
55443141400217 is an equidigital number, since it uses as much as digits as its factorization.
55443141400217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 268800, while the sum is 41.
The spelling of 55443141400217 in words is "fifty-five trillion, four hundred forty-three billion, one hundred forty-one million, four hundred thousand, two hundred seventeen".
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