Base | Representation |
---|---|
bin | 11001001101101110101110… |
… | …10111101011101111110111 |
3 | 21021022201021212221120102122 |
4 | 30212313113113223233313 |
5 | 24231422131102242012 |
6 | 313532054214030155 |
7 | 14451636632530352 |
oct | 1446672727535767 |
9 | 237281255846378 |
10 | 55447346134007 |
11 | 167380a6424213 |
12 | 627609804835b |
13 | 24c287c112389 |
14 | d9994721d299 |
15 | 6624a564de72 |
hex | 326dd75ebbf7 |
55447346134007 has 4 divisors (see below), whose sum is σ = 55449165959880. Its totient is φ = 55445526308136.
The previous prime is 55447346133967. The next prime is 55447346134051. The reversal of 55447346134007 is 70043164374455.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55447346134007 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 55447346134007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55447346134207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 909867233 + ... + 909928170.
It is an arithmetic number, because the mean of its divisors is an integer number (13862291489970).
Almost surely, 255447346134007 is an apocalyptic number.
55447346134007 is a deficient number, since it is larger than the sum of its proper divisors (1819825873).
55447346134007 is a wasteful number, since it uses less digits than its factorization.
55447346134007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1819825872.
The product of its (nonzero) digits is 16934400, while the sum is 53.
The spelling of 55447346134007 in words is "fifty-five trillion, four hundred forty-seven billion, three hundred forty-six million, one hundred thirty-four thousand, seven".
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