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554511032143 = 3819371451839
BaseRepresentation
bin10000001000110110110…
…11101101111101001111
31222000021211100001121221
420010123123231331033
533041114311012033
61102423331504211
755030205001325
oct10043333557517
91860254301557
10554511032143
111a4192026792
128b574758067
13403a0657893
141cba4ad1d15
15e65654512d
hex811b6edf4f

554511032143 has 4 divisors (see below), whose sum is σ = 554512865920. Its totient is φ = 554509198368.

The previous prime is 554511032113. The next prime is 554511032167. The reversal of 554511032143 is 341230115455.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 554511032143 - 217 = 554510901071 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 554511032099 and 554511032108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (554511032113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343983 + ... + 1107856.

It is an arithmetic number, because the mean of its divisors is an integer number (138628216480).

Almost surely, 2554511032143 is an apocalyptic number.

554511032143 is a deficient number, since it is larger than the sum of its proper divisors (1833777).

554511032143 is a wasteful number, since it uses less digits than its factorization.

554511032143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1833776.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 554511032143 its reverse (341230115455), we get a palindrome (895741147598).

The spelling of 554511032143 in words is "five hundred fifty-four billion, five hundred eleven million, thirty-two thousand, one hundred forty-three".

Divisors: 1 381937 1451839 554511032143