Base | Representation |
---|---|
bin | 11001001101111011101111… |
… | …01110001101011101111011 |
3 | 21021100101022200212212122221 |
4 | 30212331313232031131323 |
5 | 24232030432312024042 |
6 | 313535211303424511 |
7 | 14452305012141145 |
oct | 1446756756153573 |
9 | 237311280785587 |
10 | 55454331361147 |
11 | 167400603a8804 |
12 | 6277507455137 |
13 | 24c3423345184 |
14 | d9a00ac11c95 |
15 | 6627639ead67 |
hex | 326f77b8d77b |
55454331361147 has 2 divisors, whose sum is σ = 55454331361148. Its totient is φ = 55454331361146.
The previous prime is 55454331361111. The next prime is 55454331361237. The reversal of 55454331361147 is 74116313345455.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55454331361147 - 219 = 55454330836859 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55454331361094 and 55454331361103.
It is not a weakly prime, because it can be changed into another prime (55454341361147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27727165680573 + 27727165680574.
It is an arithmetic number, because the mean of its divisors is an integer number (27727165680574).
Almost surely, 255454331361147 is an apocalyptic number.
55454331361147 is a deficient number, since it is larger than the sum of its proper divisors (1).
55454331361147 is an equidigital number, since it uses as much as digits as its factorization.
55454331361147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9072000, while the sum is 52.
The spelling of 55454331361147 in words is "fifty-five trillion, four hundred fifty-four billion, three hundred thirty-one million, three hundred sixty-one thousand, one hundred forty-seven".
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