Base | Representation |
---|---|
bin | 110011101011011011… |
… | …000100101100000011 |
3 | 12022020011000001202001 |
4 | 303223123010230003 |
5 | 1402120233203103 |
6 | 41254053204431 |
7 | 4003035460534 |
oct | 635333045403 |
9 | 168204001661 |
10 | 55489350403 |
11 | 21595323283 |
12 | a907330717 |
13 | 53040c5266 |
14 | 29857b468b |
15 | 169b75e01d |
hex | ceb6c4b03 |
55489350403 has 2 divisors, whose sum is σ = 55489350404. Its totient is φ = 55489350402.
The previous prime is 55489350307. The next prime is 55489350503. The reversal of 55489350403 is 30405398455.
55489350403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55489350403 - 221 = 55487253251 is a prime.
It is not a weakly prime, because it can be changed into another prime (55489350503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27744675201 + 27744675202.
It is an arithmetic number, because the mean of its divisors is an integer number (27744675202).
Almost surely, 255489350403 is an apocalyptic number.
55489350403 is a deficient number, since it is larger than the sum of its proper divisors (1).
55489350403 is an equidigital number, since it uses as much as digits as its factorization.
55489350403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296000, while the sum is 46.
The spelling of 55489350403 in words is "fifty-five billion, four hundred eighty-nine million, three hundred fifty thousand, four hundred three".
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