Base | Representation |
---|---|
bin | 110011101100000101… |
… | …110011001101011101 |
3 | 12022020221002010002011 |
4 | 303230011303031131 |
5 | 1402131120113010 |
6 | 41255133231221 |
7 | 4003232620414 |
oct | 635405631535 |
9 | 168227063064 |
10 | 55500551005 |
11 | 215a0683479 |
12 | a90b032511 |
13 | 5306517433 |
14 | 298708c47b |
15 | 169c722a8a |
hex | cec17335d |
55500551005 has 32 divisors (see below), whose sum is σ = 71900006400. Its totient is φ = 41007267840.
The previous prime is 55500550969. The next prime is 55500551017. The reversal of 55500551005 is 50015500555.
55500551005 is digitally balanced in base 11, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55500551005 - 215 = 55500518237 is a prime.
It is a super-2 number, since 2×555005510052 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
55500551005 is strictly pandigital in base 11.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1583349 + ... + 1618021.
It is an arithmetic number, because the mean of its divisors is an integer number (2246875200).
Almost surely, 255500551005 is an apocalyptic number.
It is an amenable number.
55500551005 is a deficient number, since it is larger than the sum of its proper divisors (16399455395).
55500551005 is a wasteful number, since it uses less digits than its factorization.
55500551005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35181.
The product of its (nonzero) digits is 15625, while the sum is 31.
The spelling of 55500551005 in words is "fifty-five billion, five hundred million, five hundred fifty-one thousand, five".
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