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55514214130 = 255551421413
BaseRepresentation
bin110011101100111001…
…111010111011110010
312022021212210021100211
4303230321322323302
51402143114323010
641300342134334
74003460014534
oct635471727362
9168255707324
1055514214130
11215a8365811
12a9137213aa
1353092bc41b
142988c07854
15169da2108a
hexcece7aef2

55514214130 has 8 divisors (see below), whose sum is σ = 99925585452. Its totient is φ = 22205685648.

The previous prime is 55514214101. The next prime is 55514214139. The reversal of 55514214130 is 3141241555.

It can be written as a sum of positive squares in 2 ways, for example, as 45285116809 + 10229097321 = 212803^2 + 101139^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 55514214092 and 55514214101.

It is not an unprimeable number, because it can be changed into a prime (55514214139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2775710697 + ... + 2775710716.

Almost surely, 255514214130 is an apocalyptic number.

55514214130 is a deficient number, since it is larger than the sum of its proper divisors (44411371322).

55514214130 is a wasteful number, since it uses less digits than its factorization.

55514214130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5551421420.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 55514214130 its reverse (3141241555), we get a palindrome (58655455685).

The spelling of 55514214130 in words is "fifty-five billion, five hundred fourteen million, two hundred fourteen thousand, one hundred thirty".

Divisors: 1 2 5 10 5551421413 11102842826 27757107065 55514214130