Base | Representation |
---|---|
bin | 101000011010010110010… |
… | …1010110001000010010101 |
3 | 201122222012201021121122102 |
4 | 1100310230222301002111 |
5 | 1211444340340402013 |
6 | 15451312045211445 |
7 | 1112162551040213 |
oct | 120645452610225 |
9 | 21588181247572 |
10 | 5554142122133 |
11 | 1851553482740 |
12 | 75851ab60b85 |
13 | 3139a41746a7 |
14 | 152b71487cb3 |
15 | 99721694d58 |
hex | 50d2cab1095 |
5554142122133 has 4 divisors (see below), whose sum is σ = 6059064133248. Its totient is φ = 5049220111020.
The previous prime is 5554142122129. The next prime is 5554142122159. The reversal of 5554142122133 is 3312212414555.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5554142122133 - 22 = 5554142122129 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5554142122163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252461005541 + ... + 252461005562.
It is an arithmetic number, because the mean of its divisors is an integer number (1514766033312).
Almost surely, 25554142122133 is an apocalyptic number.
It is an amenable number.
5554142122133 is a deficient number, since it is larger than the sum of its proper divisors (504922011115).
5554142122133 is a wasteful number, since it uses less digits than its factorization.
5554142122133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 504922011114.
The product of its digits is 144000, while the sum is 38.
Adding to 5554142122133 its reverse (3312212414555), we get a palindrome (8866354536688).
The spelling of 5554142122133 in words is "five trillion, five hundred fifty-four billion, one hundred forty-two million, one hundred twenty-two thousand, one hundred thirty-three".
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