Base | Representation |
---|---|
bin | 110011101111000010… |
… | …101000000010000001 |
3 | 12022101101012221112022 |
4 | 303233002220002001 |
5 | 1402231303103213 |
6 | 41304102211225 |
7 | 4004403431543 |
oct | 635702500201 |
9 | 168341187468 |
10 | 55550050433 |
11 | 21616612099 |
12 | a923723b15 |
13 | 5313858a37 |
14 | 298d895693 |
15 | 16a1c4e308 |
hex | cef0a8081 |
55550050433 has 2 divisors, whose sum is σ = 55550050434. Its totient is φ = 55550050432.
The previous prime is 55550050429. The next prime is 55550050447. The reversal of 55550050433 is 33405005555.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 45679230529 + 9870819904 = 213727^2 + 99352^2 .
It is a cyclic number.
It is not a de Polignac number, because 55550050433 - 22 = 55550050429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55550050393 and 55550050402.
It is not a weakly prime, because it can be changed into another prime (55550050453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27775025216 + 27775025217.
It is an arithmetic number, because the mean of its divisors is an integer number (27775025217).
Almost surely, 255550050433 is an apocalyptic number.
It is an amenable number.
55550050433 is a deficient number, since it is larger than the sum of its proper divisors (1).
55550050433 is an equidigital number, since it uses as much as digits as its factorization.
55550050433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112500, while the sum is 35.
Adding to 55550050433 its reverse (33405005555), we get a palindrome (88955055988).
The spelling of 55550050433 in words is "fifty-five billion, five hundred fifty million, fifty thousand, four hundred thirty-three".
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