Base | Representation |
---|---|
bin | 101000011101000101001… |
… | …1111001010001100111011 |
3 | 201200112100201210211201022 |
4 | 1100322022133022030323 |
5 | 1212043400320330313 |
6 | 15454122302013055 |
7 | 1112461154420531 |
oct | 120721237121473 |
9 | 21615321724638 |
10 | 5560011105083 |
11 | 1853a95357476 |
12 | 75969857718b |
13 | 3143cb059a76 |
14 | 15316ab10151 |
15 | 99966a4cc08 |
hex | 50e8a7ca33b |
5560011105083 has 2 divisors, whose sum is σ = 5560011105084. Its totient is φ = 5560011105082.
The previous prime is 5560011105031. The next prime is 5560011105091. The reversal of 5560011105083 is 3805011100655.
5560011105083 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5560011105083 - 222 = 5560006910779 is a prime.
It is not a weakly prime, because it can be changed into another prime (5560011005083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2780005552541 + 2780005552542.
It is an arithmetic number, because the mean of its divisors is an integer number (2780005552542).
Almost surely, 25560011105083 is an apocalyptic number.
5560011105083 is a deficient number, since it is larger than the sum of its proper divisors (1).
5560011105083 is an equidigital number, since it uses as much as digits as its factorization.
5560011105083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 35.
The spelling of 5560011105083 in words is "five trillion, five hundred sixty billion, eleven million, one hundred five thousand, eighty-three".
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