Base | Representation |
---|---|
bin | 11001010010001100001101… |
… | …00111001010011010111011 |
3 | 21021212100220010001200222201 |
4 | 30221012012213022122323 |
5 | 24241430022133404323 |
6 | 314130322335531031 |
7 | 14466003643436623 |
oct | 1451060647123273 |
9 | 237770803050881 |
10 | 55600610059963 |
11 | 167970a4968231 |
12 | 629b92b989a77 |
13 | 2504165953267 |
14 | da3126279883 |
15 | 666475a578ad |
hex | 3291869ca6bb |
55600610059963 has 2 divisors, whose sum is σ = 55600610059964. Its totient is φ = 55600610059962.
The previous prime is 55600610059937. The next prime is 55600610060029. The reversal of 55600610059963 is 36995001600655.
55600610059963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55600610059963 - 25 = 55600610059931 is a prime.
It is a super-2 number, since 2×556006100599632 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55600610059903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27800305029981 + 27800305029982.
It is an arithmetic number, because the mean of its divisors is an integer number (27800305029982).
Almost surely, 255600610059963 is an apocalyptic number.
55600610059963 is a deficient number, since it is larger than the sum of its proper divisors (1).
55600610059963 is an equidigital number, since it uses as much as digits as its factorization.
55600610059963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6561000, while the sum is 55.
The spelling of 55600610059963 in words is "fifty-five trillion, six hundred billion, six hundred ten million, fifty-nine thousand, nine hundred sixty-three".
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