Base | Representation |
---|---|
bin | 11001010010100000001000… |
… | …11101001100101100100011 |
3 | 21021220101111220100121120211 |
4 | 30221100010131030230203 |
5 | 24242113431143433101 |
6 | 314135252252514551 |
7 | 14466533064535264 |
oct | 1451200435145443 |
9 | 237811456317524 |
10 | 55611311311651 |
11 | 167a06964a6a97 |
12 | 62a1a1777ba57 |
13 | 250517c9ca754 |
14 | da385d5c096b |
15 | 6668a0283c51 |
hex | 32940474cb23 |
55611311311651 has 2 divisors, whose sum is σ = 55611311311652. Its totient is φ = 55611311311650.
The previous prime is 55611311311607. The next prime is 55611311311669. The reversal of 55611311311651 is 15611311311655.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55611311311651 is a prime.
It is not a weakly prime, because it can be changed into another prime (55611311311601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27805655655825 + 27805655655826.
It is an arithmetic number, because the mean of its divisors is an integer number (27805655655826).
Almost surely, 255611311311651 is an apocalyptic number.
55611311311651 is a deficient number, since it is larger than the sum of its proper divisors (1).
55611311311651 is an equidigital number, since it uses as much as digits as its factorization.
55611311311651 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 40500, while the sum is 40.
The spelling of 55611311311651 in words is "fifty-five trillion, six hundred eleven billion, three hundred eleven million, three hundred eleven thousand, six hundred fifty-one".
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