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5563867968073 is a prime number
BaseRepresentation
bin101000011110111000001…
…0111111011001001001001
3201200220022112011210002201
41100331300113323021021
51212124300144434243
615500001120000201
71112655556260202
oct120756027731111
921626275153081
105563867968073
111855694466748
1275a394160061
1331489411330c
141534150445a9
1599ae044c04d
hex50f705fb249

5563867968073 has 2 divisors, whose sum is σ = 5563867968074. Its totient is φ = 5563867968072.

The previous prime is 5563867968017. The next prime is 5563867968083. The reversal of 5563867968073 is 3708697683655.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4990702384144 + 573165583929 = 2233988^2 + 757077^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5563867968073 is a prime.

It is a super-2 number, since 2×55638679680732 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5563867967987 and 5563867968005.

It is not a weakly prime, because it can be changed into another prime (5563867968083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2781933984036 + 2781933984037.

It is an arithmetic number, because the mean of its divisors is an integer number (2781933984037).

Almost surely, 25563867968073 is an apocalyptic number.

It is an amenable number.

5563867968073 is a deficient number, since it is larger than the sum of its proper divisors (1).

5563867968073 is an equidigital number, since it uses as much as digits as its factorization.

5563867968073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1371686400, while the sum is 73.

The spelling of 5563867968073 in words is "five trillion, five hundred sixty-three billion, eight hundred sixty-seven million, nine hundred sixty-eight thousand, seventy-three".