Base | Representation |
---|---|
bin | 101000011110111000001… |
… | …0111111011001001100001 |
3 | 201200220022112011210010121 |
4 | 1100331300113323021201 |
5 | 1212124300144434342 |
6 | 15500001120000241 |
7 | 1112655556260235 |
oct | 120756027731141 |
9 | 21626275153117 |
10 | 5563867968097 |
11 | 185569446676a |
12 | 75a394160081 |
13 | 31489411332a |
14 | 1534150445c5 |
15 | 99ae044c067 |
hex | 50f705fb261 |
5563867968097 has 2 divisors, whose sum is σ = 5563867968098. Its totient is φ = 5563867968096.
The previous prime is 5563867968083. The next prime is 5563867968119. The reversal of 5563867968097 is 7908697683655.
5563867968097 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4257656701281 + 1306211266816 = 2063409^2 + 1142896^2 .
It is a cyclic number.
It is not a de Polignac number, because 5563867968097 - 219 = 5563867443809 is a prime.
It is not a weakly prime, because it can be changed into another prime (5563867968017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2781933984048 + 2781933984049.
It is an arithmetic number, because the mean of its divisors is an integer number (2781933984049).
Almost surely, 25563867968097 is an apocalyptic number.
It is an amenable number.
5563867968097 is a deficient number, since it is larger than the sum of its proper divisors (1).
5563867968097 is an equidigital number, since it uses as much as digits as its factorization.
5563867968097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4115059200, while the sum is 79.
The spelling of 5563867968097 in words is "five trillion, five hundred sixty-three billion, eight hundred sixty-seven million, nine hundred sixty-eight thousand, ninety-seven".
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