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5564001433 is a prime number
BaseRepresentation
bin1010010111010001…
…11110110010011001
3112100202122120002011
411023220332302121
542343341021213
62320035505521
7254611142344
oct51350766231
915322576064
105564001433
1123a58086a1
1210b34582a1
136a8962053
143aad5745b
1522871303d
hex14ba3ec99

5564001433 has 2 divisors, whose sum is σ = 5564001434. Its totient is φ = 5564001432.

The previous prime is 5564001419. The next prime is 5564001467. The reversal of 5564001433 is 3341004655.

5564001433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5563966464 + 34969 = 74592^2 + 187^2 .

It is a cyclic number.

It is not a de Polignac number, because 5564001433 - 29 = 5564000921 is a prime.

It is a super-2 number, since 2×55640014332 = 61916223892852106978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5564001395 and 5564001404.

It is not a weakly prime, because it can be changed into another prime (5564001733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2782000716 + 2782000717.

It is an arithmetic number, because the mean of its divisors is an integer number (2782000717).

Almost surely, 25564001433 is an apocalyptic number.

It is an amenable number.

5564001433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5564001433 is an equidigital number, since it uses as much as digits as its factorization.

5564001433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

The square root of 5564001433 is about 74592.2344014442. The cubic root of 5564001433 is about 1771.9946692774.

The spelling of 5564001433 in words is "five billion, five hundred sixty-four million, one thousand, four hundred thirty-three".