Base | Representation |
---|---|
bin | 11001010110111100111010… |
… | …00011100111011000001011 |
3 | 21022110000010122200201001202 |
4 | 30223132131003213120023 |
5 | 24302120033003441403 |
6 | 314333415004534415 |
7 | 14513554513612322 |
oct | 1453363503473013 |
9 | 238400118621052 |
10 | 55764195374603 |
11 | 1684a50a579341 |
12 | 630758425140b |
13 | 251670592a921 |
14 | dab003dd90b9 |
15 | 66a84c155688 |
hex | 32b79d0e760b |
55764195374603 has 2 divisors, whose sum is σ = 55764195374604. Its totient is φ = 55764195374602.
The previous prime is 55764195374549. The next prime is 55764195374621. The reversal of 55764195374603 is 30647359146755.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55764195374603 - 232 = 55759900407307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55764195374603.
It is not a weakly prime, because it can be changed into another prime (55764195374803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27882097687301 + 27882097687302.
It is an arithmetic number, because the mean of its divisors is an integer number (27882097687302).
Almost surely, 255764195374603 is an apocalyptic number.
55764195374603 is a deficient number, since it is larger than the sum of its proper divisors (1).
55764195374603 is an equidigital number, since it uses as much as digits as its factorization.
55764195374603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 285768000, while the sum is 65.
The spelling of 55764195374603 in words is "fifty-five trillion, seven hundred sixty-four billion, one hundred ninety-five million, three hundred seventy-four thousand, six hundred three".
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