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557644741221433 is a prime number
BaseRepresentation
bin111111011001011001100100…
…0101101100001110000111001
32201010110022112211001111001011
41332302303020231201300321
51041042422412223041213
65254002242454353521
7225313334351666125
oct17662631055416071
92633408484044034
10557644741221433
11151756896718658
125266335365b8a1
131ac2089a7865b8
149b9c21428a585
15447094594d03d
hex1fb2cc8b61c39

557644741221433 has 2 divisors, whose sum is σ = 557644741221434. Its totient is φ = 557644741221432.

The previous prime is 557644741221419. The next prime is 557644741221461. The reversal of 557644741221433 is 334122147446755.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 557371282298944 + 273458922489 = 23608712^2 + 522933^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-557644741221433 is a prime.

It is not a weakly prime, because it can be changed into another prime (557644741227433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278822370610716 + 278822370610717.

It is an arithmetic number, because the mean of its divisors is an integer number (278822370610717).

Almost surely, 2557644741221433 is an apocalyptic number.

It is an amenable number.

557644741221433 is a deficient number, since it is larger than the sum of its proper divisors (1).

557644741221433 is an equidigital number, since it uses as much as digits as its factorization.

557644741221433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 67737600, while the sum is 58.

The spelling of 557644741221433 in words is "five hundred fifty-seven trillion, six hundred forty-four billion, seven hundred forty-one million, two hundred twenty-one thousand, four hundred thirty-three".