Base | Representation |
---|---|
bin | 110011111101100110… |
… | …000001101100010111 |
3 | 12100000101122121200202 |
4 | 303331212001230113 |
5 | 1403231304232412 |
6 | 41344223331115 |
7 | 4013426654651 |
oct | 637546015427 |
9 | 170011577622 |
10 | 55794211607 |
11 | 21731417a92 |
12 | a991450a9b |
13 | 53523058c4 |
14 | 29b40916d1 |
15 | 16b83cd3c2 |
hex | cfd981b17 |
55794211607 has 4 divisors (see below), whose sum is σ = 58730749080. Its totient is φ = 52857674136.
The previous prime is 55794211579. The next prime is 55794211631. The reversal of 55794211607 is 70611249755.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70611249755 = 5 ⋅14122249951.
It is a cyclic number.
It is not a de Polignac number, because 55794211607 - 232 = 51499244311 is a prime.
It is a super-2 number, since 2×557942116072 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55794211687) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1468268708 + ... + 1468268745.
It is an arithmetic number, because the mean of its divisors is an integer number (14682687270).
Almost surely, 255794211607 is an apocalyptic number.
55794211607 is a deficient number, since it is larger than the sum of its proper divisors (2936537473).
55794211607 is a wasteful number, since it uses less digits than its factorization.
55794211607 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2936537472.
The product of its (nonzero) digits is 529200, while the sum is 47.
The spelling of 55794211607 in words is "fifty-five billion, seven hundred ninety-four million, two hundred eleven thousand, six hundred seven".
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