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5591324804101 = 53733143924549
BaseRepresentation
bin101000101011101010011…
…1011011100010000000101
3201210112012001001120100121
41101113110323130100011
51213102013122212401
615520341423141541
71114650145443631
oct121272473342005
921715161046317
105591324804101
1118662a40a4a73
127637774448b1
1331734b64525a
1415489b803dc1
159a69ab70ca1
hex515d4edc405

5591324804101 has 8 divisors (see below), whose sum is σ = 5704593463800. Its totient is φ = 5478343995072.

The previous prime is 5591324804099. The next prime is 5591324804123. The reversal of 5591324804101 is 1014084231955.

It can be written as a sum of positive squares in 4 ways, for example, as 1158047167876 + 4433277636225 = 1076126^2 + 2105535^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5591324804101 - 21 = 5591324804099 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5591324804141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71923426 + ... + 72001123.

It is an arithmetic number, because the mean of its divisors is an integer number (713074182975).

Almost surely, 25591324804101 is an apocalyptic number.

It is an amenable number.

5591324804101 is a deficient number, since it is larger than the sum of its proper divisors (113268659699).

5591324804101 is a wasteful number, since it uses less digits than its factorization.

5591324804101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143925335.

The product of its (nonzero) digits is 172800, while the sum is 43.

The spelling of 5591324804101 in words is "five trillion, five hundred ninety-one billion, three hundred twenty-four million, eight hundred four thousand, one hundred one".

Divisors: 1 53 733 38849 143924549 7628001097 105496694417 5591324804101