Base | Representation |
---|---|
bin | 110100001100111001… |
… | …100110001100110001 |
3 | 12100200021211211022011 |
4 | 310030321212030301 |
5 | 1404243024000423 |
6 | 41425515242521 |
7 | 4022665432333 |
oct | 641471461461 |
9 | 170607754264 |
10 | 56051000113 |
11 | 21853367a99 |
12 | aa43449441 |
13 | 5393584174 |
14 | 29da217453 |
15 | 16d0c03b0d |
hex | d0ce66331 |
56051000113 has 2 divisors, whose sum is σ = 56051000114. Its totient is φ = 56051000112.
The previous prime is 56051000063. The next prime is 56051000129. The reversal of 56051000113 is 31100015065.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51743965729 + 4307034384 = 227473^2 + 65628^2 .
It is a cyclic number.
It is not a de Polignac number, because 56051000113 - 213 = 56050991921 is a prime.
It is a super-2 number, since 2×560510001132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (56051000143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28025500056 + 28025500057.
It is an arithmetic number, because the mean of its divisors is an integer number (28025500057).
Almost surely, 256051000113 is an apocalyptic number.
It is an amenable number.
56051000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
56051000113 is an equidigital number, since it uses as much as digits as its factorization.
56051000113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 56051000113 its reverse (31100015065), we get a palindrome (87151015178).
The spelling of 56051000113 in words is "fifty-six billion, fifty-one million, one hundred thirteen", and thus it is an aban number.
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