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560551001113 is a prime number
BaseRepresentation
bin10000010100000110111…
…00010111110000011001
31222120212202121021102101
420022003130113300121
533141002024013423
61105302533203401
755332655615315
oct10120334276031
91876782537371
10560551001113
111a6801476884
129077b490561
1340b23aa900c
141d1b8d46b45
15e8ab9257ad
hex8283717c19

560551001113 has 2 divisors, whose sum is σ = 560551001114. Its totient is φ = 560551001112.

The previous prime is 560551001093. The next prime is 560551001159. The reversal of 560551001113 is 311100155065.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 337778328969 + 222772672144 = 581187^2 + 471988^2 .

It is a cyclic number.

It is not a de Polignac number, because 560551001113 - 225 = 560517446681 is a prime.

It is not a weakly prime, because it can be changed into another prime (560561001113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280275500556 + 280275500557.

It is an arithmetic number, because the mean of its divisors is an integer number (280275500557).

Almost surely, 2560551001113 is an apocalyptic number.

It is an amenable number.

560551001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

560551001113 is an equidigital number, since it uses as much as digits as its factorization.

560551001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2250, while the sum is 28.

Adding to 560551001113 its reverse (311100155065), we get a palindrome (871651156178).

The spelling of 560551001113 in words is "five hundred sixty billion, five hundred fifty-one million, one thousand, one hundred thirteen".