Base | Representation |
---|---|
bin | 11001100000111000110100… |
… | …11010101110011000010011 |
3 | 21100122122100210121111012111 |
4 | 30300130122122232120103 |
5 | 24323213232324012404 |
6 | 315154320212210151 |
7 | 14550332044553605 |
oct | 1460343232563023 |
9 | 240578323544174 |
10 | 56105601000979 |
11 | 16971285105572 |
12 | 6361784309957 |
13 | 253c973aaa46a |
14 | dbd750283175 |
15 | 67467e903104 |
hex | 33071a6ae613 |
56105601000979 has 2 divisors, whose sum is σ = 56105601000980. Its totient is φ = 56105601000978.
The previous prime is 56105601000971. The next prime is 56105601001019. The reversal of 56105601000979 is 97900010650165.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56105601000979 - 23 = 56105601000971 is a prime.
It is not a weakly prime, because it can be changed into another prime (56105601000971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28052800500489 + 28052800500490.
It is an arithmetic number, because the mean of its divisors is an integer number (28052800500490).
Almost surely, 256105601000979 is an apocalyptic number.
56105601000979 is a deficient number, since it is larger than the sum of its proper divisors (1).
56105601000979 is an equidigital number, since it uses as much as digits as its factorization.
56105601000979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 510300, while the sum is 49.
The spelling of 56105601000979 in words is "fifty-six trillion, one hundred five billion, six hundred one million, nine hundred seventy-nine", and thus it is an aban number.
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