Base | Representation |
---|---|
bin | 11001100001000111100111… |
… | …10011010000110000010001 |
3 | 21100200101212021222201002022 |
4 | 30300203303303100300101 |
5 | 24323331014010301101 |
6 | 315202112242101225 |
7 | 14551032623120255 |
oct | 1460436363206021 |
9 | 240611767881068 |
10 | 56113543056401 |
11 | 169746901a6336 |
12 | 636322004a815 |
13 | 254063b31303c |
14 | dbdca4d86265 |
15 | 674996ca4a1b |
hex | 3308f3cd0c11 |
56113543056401 has 2 divisors, whose sum is σ = 56113543056402. Its totient is φ = 56113543056400.
The previous prime is 56113543056349. The next prime is 56113543056497. The reversal of 56113543056401 is 10465034531165.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43399754446801 + 12713788609600 = 6587849^2 + 3565640^2 .
It is a cyclic number.
It is not a de Polignac number, because 56113543056401 - 234 = 56096363187217 is a prime.
It is not a weakly prime, because it can be changed into another prime (56113543056101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28056771528200 + 28056771528201.
It is an arithmetic number, because the mean of its divisors is an integer number (28056771528201).
Almost surely, 256113543056401 is an apocalyptic number.
It is an amenable number.
56113543056401 is a deficient number, since it is larger than the sum of its proper divisors (1).
56113543056401 is an equidigital number, since it uses as much as digits as its factorization.
56113543056401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 44.
Adding to 56113543056401 its reverse (10465034531165), we get a palindrome (66578577587566).
The spelling of 56113543056401 in words is "fifty-six trillion, one hundred thirteen billion, five hundred forty-three million, fifty-six thousand, four hundred one".
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