Base | Representation |
---|---|
bin | 110100010000110101… |
… | …101111111111010001 |
3 | 12100211220020001222112 |
4 | 310100311233333101 |
5 | 1404411434203442 |
6 | 41440240115105 |
7 | 4024430324663 |
oct | 642065577721 |
9 | 170756201875 |
10 | 56117100497 |
11 | 21887705207 |
12 | aa61605a95 |
13 | 53a4188a13 |
14 | 2a04d02533 |
15 | 16d690e082 |
hex | d10d6ffd1 |
56117100497 has 2 divisors, whose sum is σ = 56117100498. Its totient is φ = 56117100496.
The previous prime is 56117100461. The next prime is 56117100509. The reversal of 56117100497 is 79400171165.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34683847696 + 21433252801 = 186236^2 + 146401^2 .
It is a cyclic number.
It is not a de Polignac number, because 56117100497 - 210 = 56117099473 is a prime.
It is not a weakly prime, because it can be changed into another prime (56117100407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28058550248 + 28058550249.
It is an arithmetic number, because the mean of its divisors is an integer number (28058550249).
Almost surely, 256117100497 is an apocalyptic number.
It is an amenable number.
56117100497 is a deficient number, since it is larger than the sum of its proper divisors (1).
56117100497 is an equidigital number, since it uses as much as digits as its factorization.
56117100497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 52920, while the sum is 41.
The spelling of 56117100497 in words is "fifty-six billion, one hundred seventeen million, one hundred thousand, four hundred ninety-seven".
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