Base | Representation |
---|---|
bin | 110100010000111000… |
… | …100011001000111111 |
3 | 12100211221121100120112 |
4 | 310100320203020333 |
5 | 1404412131144203 |
6 | 41440303540235 |
7 | 4024436502236 |
oct | 642070431077 |
9 | 170757540515 |
10 | 56117834303 |
11 | 21888066563 |
12 | aa618ba67b |
13 | 53a4384a1b |
14 | 2a05053b1d |
15 | 16d6a066d8 |
hex | d10e2323f |
56117834303 has 4 divisors (see below), whose sum is σ = 56118576360. Its totient is φ = 56117092248.
The previous prime is 56117834281. The next prime is 56117834321. The reversal of 56117834303 is 30343871165.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 56117834303 - 212 = 56117830207 is a prime.
It is a super-2 number, since 2×561178343032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56117834323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242825 + ... + 413762.
It is an arithmetic number, because the mean of its divisors is an integer number (14029644090).
Almost surely, 256117834303 is an apocalyptic number.
56117834303 is a deficient number, since it is larger than the sum of its proper divisors (742057).
56117834303 is an equidigital number, since it uses as much as digits as its factorization.
56117834303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 742056.
The product of its (nonzero) digits is 181440, while the sum is 41.
The spelling of 56117834303 in words is "fifty-six billion, one hundred seventeen million, eight hundred thirty-four thousand, three hundred three".
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