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5614145113 is a prime number
BaseRepresentation
bin1010011101010000…
…10000111001011001
3112111021000010021111
411032220100321121
542444210120423
62325030340321
7256060306003
oct51650207131
915437003244
105614145113
112421047355
1211081ba6a1
136b616a975
143b388b373
1522cd1a60d
hex14ea10e59

5614145113 has 2 divisors, whose sum is σ = 5614145114. Its totient is φ = 5614145112.

The previous prime is 5614145077. The next prime is 5614145179. The reversal of 5614145113 is 3115414165.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5593095369 + 21049744 = 74787^2 + 4588^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5614145113 is a prime.

It is not a weakly prime, because it can be changed into another prime (5614145183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2807072556 + 2807072557.

It is an arithmetic number, because the mean of its divisors is an integer number (2807072557).

Almost surely, 25614145113 is an apocalyptic number.

It is an amenable number.

5614145113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5614145113 is an equidigital number, since it uses as much as digits as its factorization.

5614145113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7200, while the sum is 31.

The square root of 5614145113 is about 74927.5991407706. The cubic root of 5614145113 is about 1777.3019252132.

Adding to 5614145113 its reverse (3115414165), we get a palindrome (8729559278).

The spelling of 5614145113 in words is "five billion, six hundred fourteen million, one hundred forty-five thousand, one hundred thirteen".