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561573131427073 is a prime number
BaseRepresentation
bin111111110101111110110111…
…1000000111001110100000001
32201122100212102002021201101101
41333223331233000321310001
51042101303233121131243
65310211045102134401
7226200214464540463
oct17753755700716401
92648325362251341
10561573131427073
11152a30911566897
1252b98775581401
131b14717178283c
149c963dac90133
1544dcc14d1154d
hex1febf6f039d01

561573131427073 has 2 divisors, whose sum is σ = 561573131427074. Its totient is φ = 561573131427072.

The previous prime is 561573131427053. The next prime is 561573131427089. The reversal of 561573131427073 is 370724131375165.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 417878920915569 + 143694210511504 = 20442087^2 + 11987252^2 .

It is a cyclic number.

It is not a de Polignac number, because 561573131427073 - 241 = 559374108171521 is a prime.

It is not a weakly prime, because it can be changed into another prime (561573131427013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280786565713536 + 280786565713537.

It is an arithmetic number, because the mean of its divisors is an integer number (280786565713537).

Almost surely, 2561573131427073 is an apocalyptic number.

It is an amenable number.

561573131427073 is a deficient number, since it is larger than the sum of its proper divisors (1).

561573131427073 is an equidigital number, since it uses as much as digits as its factorization.

561573131427073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11113200, while the sum is 55.

The spelling of 561573131427073 in words is "five hundred sixty-one trillion, five hundred seventy-three billion, one hundred thirty-one million, four hundred twenty-seven thousand, seventy-three".