Base | Representation |
---|---|
bin | 101000111010000110111… |
… | …1010011110011110010101 |
3 | 201220111020221012110121120 |
4 | 1101310031322132132111 |
5 | 1214104030434422240 |
6 | 15542511523034153 |
7 | 1120125652164315 |
oct | 121641572363625 |
9 | 21814227173546 |
10 | 5622345623445 |
11 | 1878472591751 |
12 | 76979420b959 |
13 | 31a253356865 |
14 | 1561a1659445 |
15 | 9b3b41dead0 |
hex | 51d0de9e795 |
5622345623445 has 16 divisors (see below), whose sum is σ = 9386872693632. Its totient is φ = 2868211100480.
The previous prime is 5622345623423. The next prime is 5622345623467. The reversal of 5622345623445 is 5443265432265.
It is an interprime number because it is at equal distance from previous prime (5622345623423) and next prime (5622345623467).
It is not a de Polignac number, because 5622345623445 - 28 = 5622345623189 is a prime.
It is a super-3 number, since 3×56223456234453 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8148326646 + ... + 8148327335.
It is an arithmetic number, because the mean of its divisors is an integer number (586679543352).
Almost surely, 25622345623445 is an apocalyptic number.
It is an amenable number.
5622345623445 is a deficient number, since it is larger than the sum of its proper divisors (3764527070187).
5622345623445 is a wasteful number, since it uses less digits than its factorization.
5622345623445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16296654012.
The product of its digits is 20736000, while the sum is 51.
The spelling of 5622345623445 in words is "five trillion, six hundred twenty-two billion, three hundred forty-five million, six hundred twenty-three thousand, four hundred forty-five".
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