Base | Representation |
---|---|
bin | 110100010111100100… |
… | …111101111101101001 |
3 | 12101010202221011111111 |
4 | 310113210331331221 |
5 | 1410124404014201 |
6 | 41455355030321 |
7 | 4030302214321 |
oct | 642744757551 |
9 | 171122834444 |
10 | 56230141801 |
11 | 219354a3879 |
12 | aa9343b3a1 |
13 | 53c1717472 |
14 | 2a15d2a281 |
15 | 16e17dcb51 |
hex | d1793df69 |
56230141801 has 2 divisors, whose sum is σ = 56230141802. Its totient is φ = 56230141800.
The previous prime is 56230141789. The next prime is 56230141823. The reversal of 56230141801 is 10814103265.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54079037401 + 2151104400 = 232549^2 + 46380^2 .
It is a cyclic number.
It is not a de Polignac number, because 56230141801 - 25 = 56230141769 is a prime.
It is a super-3 number, since 3×562301418013 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (56230151801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28115070900 + 28115070901.
It is an arithmetic number, because the mean of its divisors is an integer number (28115070901).
Almost surely, 256230141801 is an apocalyptic number.
It is an amenable number.
56230141801 is a deficient number, since it is larger than the sum of its proper divisors (1).
56230141801 is an equidigital number, since it uses as much as digits as its factorization.
56230141801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
The spelling of 56230141801 in words is "fifty-six billion, two hundred thirty million, one hundred forty-one thousand, eight hundred one".
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