Base | Representation |
---|---|
bin | 101000111011011001111… |
… | …1110100100100111111011 |
3 | 201220202110002201120211011 |
4 | 1101312303332210213323 |
5 | 1214130232204340232 |
6 | 15544052210414351 |
7 | 1120255002444364 |
oct | 121666376444773 |
9 | 21822402646734 |
10 | 5625131715067 |
11 | 187967222a607 |
12 | 76a2312913b7 |
13 | 31a5a8624297 |
14 | 15638769cb6b |
15 | 9b4c8acd547 |
hex | 51db3fa49fb |
5625131715067 has 2 divisors, whose sum is σ = 5625131715068. Its totient is φ = 5625131715066.
The previous prime is 5625131715023. The next prime is 5625131715103. The reversal of 5625131715067 is 7605171315265.
5625131715067 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5625131715067 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5625131715067.
It is not a weakly prime, because it can be changed into another prime (5625131715767) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2812565857533 + 2812565857534.
It is an arithmetic number, because the mean of its divisors is an integer number (2812565857534).
Almost surely, 25625131715067 is an apocalyptic number.
5625131715067 is a deficient number, since it is larger than the sum of its proper divisors (1).
5625131715067 is an equidigital number, since it uses as much as digits as its factorization.
5625131715067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1323000, while the sum is 49.
The spelling of 5625131715067 in words is "five trillion, six hundred twenty-five billion, one hundred thirty-one million, seven hundred fifteen thousand, sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •