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563411316542257 is a prime number
BaseRepresentation
bin1000000000011010110110101…
…1011000101000101100110001
32201212212121002100212201102101
42000012231223120220230301
51042321412334013323012
65314135330300420401
7226450060435322131
oct20006555330505461
92655777070781371
10563411316542257
1115357a4410a3707
1253234a79b47701
131b24b5c7a78151
149d1b378b9aac1
15452094bd57d57
hex2006b6b628b31

563411316542257 has 2 divisors, whose sum is σ = 563411316542258. Its totient is φ = 563411316542256.

The previous prime is 563411316542233. The next prime is 563411316542267. The reversal of 563411316542257 is 752245613114365.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 563120446165281 + 290870376976 = 23730159^2 + 539324^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-563411316542257 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 563411316542198 and 563411316542207.

It is not a weakly prime, because it can be changed into another prime (563411316542267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 281705658271128 + 281705658271129.

It is an arithmetic number, because the mean of its divisors is an integer number (281705658271129).

Almost surely, 2563411316542257 is an apocalyptic number.

It is an amenable number.

563411316542257 is a deficient number, since it is larger than the sum of its proper divisors (1).

563411316542257 is an equidigital number, since it uses as much as digits as its factorization.

563411316542257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 18144000, while the sum is 55.

The spelling of 563411316542257 in words is "five hundred sixty-three trillion, four hundred eleven billion, three hundred sixteen million, five hundred forty-two thousand, two hundred fifty-seven".