Search a number
-
+
56404325375969 is a prime number
BaseRepresentation
bin11001101001100101001111…
…10001110001111111100001
321101201012102102020001101212
430310302213301301333201
524343112024244012334
6315543442300235505
714611035523056014
oct1464624761617741
9241635372201355
1056404325375969
1116a76a3824291a
1263ab65253bb95
132561b9c55696c
14dcddabc0b37b
1567c3150d8ece
hex334ca7c71fe1

56404325375969 has 2 divisors, whose sum is σ = 56404325375970. Its totient is φ = 56404325375968.

The previous prime is 56404325375897. The next prime is 56404325376001. The reversal of 56404325375969 is 96957352340465.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55752923036944 + 651402339025 = 7466788^2 + 807095^2 .

It is a cyclic number.

It is not a de Polignac number, because 56404325375969 - 212 = 56404325371873 is a prime.

It is a super-2 number, since 2×564043253759692 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 56404325375899 and 56404325375908.

It is not a weakly prime, because it can be changed into another prime (56404325375569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28202162687984 + 28202162687985.

It is an arithmetic number, because the mean of its divisors is an integer number (28202162687985).

Almost surely, 256404325375969 is an apocalyptic number.

It is an amenable number.

56404325375969 is a deficient number, since it is larger than the sum of its proper divisors (1).

56404325375969 is an equidigital number, since it uses as much as digits as its factorization.

56404325375969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 734832000, while the sum is 68.

The spelling of 56404325375969 in words is "fifty-six trillion, four hundred four billion, three hundred twenty-five million, three hundred seventy-five thousand, nine hundred sixty-nine".