Base | Representation |
---|---|
bin | 1000000001101010011011100… |
… | …0001010110111010111101011 |
3 | 2202001201021210001211100022001 |
4 | 2000122212320022313113223 |
5 | 1043011312133010044331 |
6 | 5321103341145311431 |
7 | 226650615234230611 |
oct | 20032467012672753 |
9 | 2661637701740261 |
10 | 564778404378091 |
11 | 153a571a358a922 |
12 | 53415a08a95577 |
13 | 1b31a4b4b7a567 |
14 | 9d675c629b6b1 |
15 | 45462b089a561 |
hex | 201a9b82b75eb |
564778404378091 has 2 divisors, whose sum is σ = 564778404378092. Its totient is φ = 564778404378090.
The previous prime is 564778404378073. The next prime is 564778404378151. The reversal of 564778404378091 is 190873404877465.
564778404378091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 564778404378091 - 213 = 564778404369899 is a prime.
It is not a weakly prime, because it can be changed into another prime (564778404378011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282389202189045 + 282389202189046.
It is an arithmetic number, because the mean of its divisors is an integer number (282389202189046).
Almost surely, 2564778404378091 is an apocalyptic number.
564778404378091 is a deficient number, since it is larger than the sum of its proper divisors (1).
564778404378091 is an equidigital number, since it uses as much as digits as its factorization.
564778404378091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1137991680, while the sum is 73.
The spelling of 564778404378091 in words is "five hundred sixty-four trillion, seven hundred seventy-eight billion, four hundred four million, three hundred seventy-eight thousand, ninety-one".
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