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565010100113 is a prime number
BaseRepresentation
bin10000011100011010011…
…10011110111110010001
32000000101112011222022012
420032031032132332101
533224120041200423
61111321223152305
755551322416044
oct10161516367621
92000345158265
10565010100113
111a868a520968
12916048a5695
1341384861b34
141d4bd246c5b
15ea6d135078
hex838d39ef91

565010100113 has 2 divisors, whose sum is σ = 565010100114. Its totient is φ = 565010100112.

The previous prime is 565010100101. The next prime is 565010100143. The reversal of 565010100113 is 311001010565.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 458096141584 + 106913958529 = 676828^2 + 326977^2 .

It is a cyclic number.

It is not a de Polignac number, because 565010100113 - 210 = 565010099089 is a prime.

It is a super-2 number, since 2×5650101001132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (565010100143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282505050056 + 282505050057.

It is an arithmetic number, because the mean of its divisors is an integer number (282505050057).

Almost surely, 2565010100113 is an apocalyptic number.

It is an amenable number.

565010100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

565010100113 is an equidigital number, since it uses as much as digits as its factorization.

565010100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 565010100113 its reverse (311001010565), we get a palindrome (876011110678).

The spelling of 565010100113 in words is "five hundred sixty-five billion, ten million, one hundred thousand, one hundred thirteen".