Base | Representation |
---|---|
bin | 11001101100101111000110… |
… | …11011100000111001100011 |
3 | 21102002120011020212100220112 |
4 | 30312113203123200321203 |
5 | 24401401002242313042 |
6 | 320105324240201535 |
7 | 14621623253143352 |
oct | 1466274333407143 |
9 | 242076136770815 |
10 | 56512700354147 |
11 | 170089a1080a94 |
12 | 64086590092ab |
13 | 256c18119999b |
14 | dd532d265999 |
15 | 6800596dd982 |
hex | 3365e36e0e63 |
56512700354147 has 2 divisors, whose sum is σ = 56512700354148. Its totient is φ = 56512700354146.
The previous prime is 56512700354119. The next prime is 56512700354171. The reversal of 56512700354147 is 74145300721565.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56512700354147 - 218 = 56512700092003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 56512700354095 and 56512700354104.
It is not a weakly prime, because it can be changed into another prime (56512700354447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28256350177073 + 28256350177074.
It is an arithmetic number, because the mean of its divisors is an integer number (28256350177074).
Almost surely, 256512700354147 is an apocalyptic number.
56512700354147 is a deficient number, since it is larger than the sum of its proper divisors (1).
56512700354147 is an equidigital number, since it uses as much as digits as its factorization.
56512700354147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3528000, while the sum is 50.
The spelling of 56512700354147 in words is "fifty-six trillion, five hundred twelve billion, seven hundred million, three hundred fifty-four thousand, one hundred forty-seven".
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