Base | Representation |
---|---|
bin | 1010100001111010… |
… | …01111110001010001 |
3 | 112120222111022110001 |
4 | 11100331033301101 |
5 | 43034204344303 |
6 | 2332543410001 |
7 | 260043256342 |
oct | 52075176121 |
9 | 15528438401 |
10 | 5653199953 |
11 | 24410a1885 |
12 | 11192b3901 |
13 | 6c129323b |
14 | 3b8b360c9 |
15 | 23148231d |
hex | 150f4fc51 |
5653199953 has 2 divisors, whose sum is σ = 5653199954. Its totient is φ = 5653199952.
The previous prime is 5653199939. The next prime is 5653199957. The reversal of 5653199953 is 3599913565.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4563407809 + 1089792144 = 67553^2 + 33012^2 .
It is a cyclic number.
It is not a de Polignac number, because 5653199953 - 29 = 5653199441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5653199894 and 5653199903.
It is not a weakly prime, because it can be changed into another prime (5653199957) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2826599976 + 2826599977.
It is an arithmetic number, because the mean of its divisors is an integer number (2826599977).
Almost surely, 25653199953 is an apocalyptic number.
It is an amenable number.
5653199953 is a deficient number, since it is larger than the sum of its proper divisors (1).
5653199953 is an equidigital number, since it uses as much as digits as its factorization.
5653199953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4920750, while the sum is 55.
The square root of 5653199953 is about 75187.7646495758. The cubic root of 5653199953 is about 1781.4136765438.
The spelling of 5653199953 in words is "five billion, six hundred fifty-three million, one hundred ninety-nine thousand, nine hundred fifty-three".
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