Base | Representation |
---|---|
bin | 110100101010000011… |
… | …100000001111010011 |
3 | 12101221101020112011001 |
4 | 310222003200033103 |
5 | 1411243233331103 |
6 | 41550231202431 |
7 | 4041055141552 |
oct | 645203401723 |
9 | 171841215131 |
10 | 56540136403 |
11 | 21a84484363 |
12 | ab5b216417 |
13 | 5440a0451a |
14 | 2a45181d99 |
15 | 170db2301d |
hex | d2a0e03d3 |
56540136403 has 2 divisors, whose sum is σ = 56540136404. Its totient is φ = 56540136402.
The previous prime is 56540136371. The next prime is 56540136509. The reversal of 56540136403 is 30463104565.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56540136403 - 25 = 56540136371 is a prime.
It is not a weakly prime, because it can be changed into another prime (56540136203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28270068201 + 28270068202.
It is an arithmetic number, because the mean of its divisors is an integer number (28270068202).
Almost surely, 256540136403 is an apocalyptic number.
56540136403 is a deficient number, since it is larger than the sum of its proper divisors (1).
56540136403 is an equidigital number, since it uses as much as digits as its factorization.
56540136403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 56540136403 in words is "fifty-six billion, five hundred forty million, one hundred thirty-six thousand, four hundred three".
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